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Table 1 An example showing how Bray-Curtis dissimilarity was calculated between strain I and strain J. (Note: dissimilarity calculation in real case would be more complex because typical microbial genomes usually comprise thousands of genes)

From: Gene content dissimilarity for subclassification of highly similar microbial strains

Orthologous groups # genes mapped in strain I # genes mapped in strain J C n * C ij # S i $ S j % BC ij &
OG1 1 1 1 7 9 11 0.3
OG2 2 4 2
OG3 4 2 2
OG4 0 2 0
OG5 2 2 2
  1. * C n was the number of common genes assigned to the same orthologous group, the lesser number of mapped genes was used
  2. # C ij was the sum of C n , and represented the total number of genes assigned to common orthologous groups between strain I and J
  3. $ S i was the total number of genes in strain I mapped to orthologous groups in eggNOG database
  4. % S j was the total number of genes in strain J mapped to orthologous groups in eggNOG database
  5. & BC ij is the Bray-Curtis dissimilarity between strain I and J