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Table 1 An example showing how Bray-Curtis dissimilarity was calculated between strain I and strain J. (Note: dissimilarity calculation in real case would be more complex because typical microbial genomes usually comprise thousands of genes)

From: Gene content dissimilarity for subclassification of highly similar microbial strains

Orthologous groups

# genes mapped in strain I

# genes mapped in strain J

C n *

C ij #

S i $

S j %

BC ij &

OG1

1

1

1

7

9

11

0.3

OG2

2

4

2

OG3

4

2

2

OG4

0

2

0

OG5

2

2

2

  1. * C n was the number of common genes assigned to the same orthologous group, the lesser number of mapped genes was used
  2. # C ij was the sum of C n , and represented the total number of genes assigned to common orthologous groups between strain I and J
  3. $ S i was the total number of genes in strain I mapped to orthologous groups in eggNOG database
  4. % S j was the total number of genes in strain J mapped to orthologous groups in eggNOG database
  5. & BC ij is the Bray-Curtis dissimilarity between strain I and J